Longest Consecutive Sequence
Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]
. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1] Output: 9
class Solution:
def longestConsecutive(self, n: List[int]) -> int:
ns = set(n)
lgt = 0
for i in n:
#seq start or not?
if i-1 not in ns:
lth = 0
while i + lth in ns:
lth += 1
lgt = max(lth, lgt)
return lgt
Explaination :
Comments
Post a Comment