Leetcode 424. Longest Repeating Character Replacement. Python (Sliding Window)

424. Longest Repeating Character Replacement

You are given a string s and an integer k. You can choose any character of the string and change it to any other uppercase English character. You can perform this operation at most k times.

Return the length of the longest substring containing the same letter you can get after performing the above operations.

Example 1:

Input: s = "ABAB", k = 2
Output: 4
Explanation: Replace the two 'A's with two 'B's or vice versa.

Example 2:

Input: s = "AABABBA", k = 1
Output: 4
Explanation: Replace the one 'A' in the middle with 'B' and form "AABBBBA".
The substring "BBBB" has the longest repeating letters, which is 4.

Constraints:

1 <= s.length <= 105
s consists of only uppercase English letters.
0 <= k <= s.length

Solution :

class Solution:
    def characterReplacement(self, s: str, k: int) -> int:
        hm = {}
        ans = 0
        
        l = 0
        for r in range(len(s)):
            hm[s[r]] = 1 + hm.get(s[r],0)
            
            while (r-l+1) - max(hm.values()) > k:
                hm[s[l]] -= 1
                l += 1
                
            ans = max(ans, r-l+1)
        return ans

Explaination :

Comments

Leetcode 371. Sum of Two Integers. C++ / Java

371 . Sum of Two Integers Given two integers a and b , return the sum of the two integers without using the operators + and - . Example 1: Input: a = 1, b = 2 Output: 3 Example 2: Input: a = 2, b = 3 Output: 5 Constraints: -1000 <= a, b <= 1000 Solution : C++ : class Solution { public: int getSum(int a, int b) { if (b==0) return a; int sum = a ^ b; int cr = (unsigned int) (a & b) << 1; return getSum(sum, cr); } }; Java : class Solution { public int getSum(int a, int b) { while(b != 0){ int tmp = (a & b) << 1; a = a ^ b; b = tmp; } return a; } } Explaination :

Leetcode 242. Valid Anagram. Python (3 Ways)

242 . Valid Anagram Given two strings s and t , return true if t is an anagram of s , and false otherwise . An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. Example 1: Input: s = "anagram", t = "nagaram" Output: true Example 2: Input: s = "rat", t = "car" Output: false Constraints: 1 <= s.length, t.length <= 5 * 10 4 s and t consist of lowercase English letters. Follow up: What if the inputs contain Unicode characters? How would you adapt your solution to such a case? class Solution: def isAnagram(self, s: str, t: str) -> bool: return sorted(s) == sorted(t) # return Counter(s) == Counter(t) # cs, ct = {}, {} # if len(s) != len(t): # return False # for i in range(len(s)): # cs[s[i]] = 1 + cs.get(s[i], 0) #

LEETCODE SOLUTIONS

Search This Blog