Skip to main content

Leetcode 647. Palindromic Substrings. Python (O(n^2))

647Palindromic Substrings 


Given a string s, return the number of palindromic substrings in it.

A string is a palindrome when it reads the same backward as forward.

substring is a contiguous sequence of characters within the string.

 

Example 1:

Input: s = "abc"
Output: 3
Explanation: Three palindromic strings: "a", "b", "c".

Example 2:

Input: s = "aaa"
Output: 6
Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".

 

Constraints:

  • 1 <= s.length <= 1000
  • s consists of lowercase English letters.


Solution :


class Solution:
    def countSubstrings(self, s: str) -> int:
        ans = 0
        
        for i in range(len(s)):
            ans += self.pcount(s, i, i)
            ans += self.pcount(s, i, i+1)

        return ans
    
    def pcount(self, s, l, r):
        ans = 0
        while l >= 0 and r < len(s) and s[l] == s[r]:
            ans += 1
            l -= 1
            r += 1
        return ans



Explanation :







Comments

Popular posts from this blog

Leetcode 424. Longest Repeating Character Replacement. Python (Sliding Window)

  424 .  Longest Repeating Character Replacement You are given a string  s  and an integer  k . You can choose any character of the string and change it to any other uppercase English character. You can perform this operation at most  k  times. Return  the length of the longest substring containing the same letter you can get after performing the above operations .   Example 1: Input: s = "ABAB", k = 2 Output: 4 Explanation: Replace the two 'A's with two 'B's or vice versa. Example 2: Input: s = "AABABBA", k = 1 Output: 4 Explanation: Replace the one 'A' in the middle with 'B' and form "AABBBBA". The substring "BBBB" has the longest repeating letters, which is 4.   Constraints: 1 <= s.length <= 10 5 s  consists of only uppercase English letters. 0 <= k <= s.length Solution :  class Solution: def characterReplacement(self, s: str, k: int) -> int: hm = {} ans = 0

Leetcode 371. Sum of Two Integers. C++ / Java

371 .  Sum of Two Integers   Given two integers  a  and  b , return  the sum of the two integers without using the operators   +   and   - .   Example 1: Input: a = 1, b = 2 Output: 3 Example 2: Input: a = 2, b = 3 Output: 5   Constraints: -1000 <= a, b <= 1000 Solution :  C++ : class Solution { public: int getSum(int a, int b) { if (b==0) return a; int sum = a ^ b; int cr = (unsigned int) (a & b) << 1; return getSum(sum, cr); } }; Java :  class Solution { public int getSum(int a, int b) { while(b != 0){ int tmp = (a & b) << 1; a = a ^ b; b = tmp; } return a; } } Explaination :

Leetcode 242. Valid Anagram. Python (3 Ways)

  242 .  Valid Anagram Given two strings  s  and  t , return  true   if   t   is an anagram of   s , and   false   otherwise . An  Anagram  is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.   Example 1: Input: s = "anagram", t = "nagaram" Output: true Example 2: Input: s = "rat", t = "car" Output: false   Constraints: 1 <= s.length, t.length <= 5 * 10 4 s  and  t  consist of lowercase English letters.   Follow up:  What if the inputs contain Unicode characters? How would you adapt your solution to such a case? class Solution: def isAnagram(self, s: str, t: str) -> bool: return sorted(s) == sorted(t) # return Counter(s) == Counter(t) # cs, ct = {}, {} # if len(s) != len(t): # return False # for i in range(len(s)): # cs[s[i]] = 1 + cs.get(s[i], 0) #