Skip to main content

Leetcode 61. Alien Dictionary. Python

 

There is a new alien language which uses the latin alphabet. However, the order among letters are unknown to you. You receive a list of non-empty words from the dictionary, where words are sorted lexicographically by the rules of this new language. Derive the order of letters in this language.

Example

Example 1:

Input:["wrt","wrf","er","ett","rftt"]
Output:"wertf"
Explanation:
from "wrt"and"wrf" ,we can get 't'<'f'
from "wrt"and"er" ,we can get 'w'<'e'
from "er"and"ett" ,we can get 'r'<'t'
from "ett"and"rftt" ,we can get 'e'<'r'
So return "wertf"

Example 2:

Input:["z","x"]
Output:"zx"
Explanation:
from "z" and "x",we can get 'z' < 'x'
So return "zx"
Solution :
from typing import (
    List,
)

class Solution:
    def alien_order(self, words: List[str]) -> str:
        adj = { c:set() for w in words for c in w}

        for i in range(len(words)-1):
            w1, w2 = words[i], words[i+1]
            lmin = min(len(w1), len(w2))
            if len(w1) > len(w2) and w1[:lmin] == w2[:lmin] :
                return ""
            for j in range(lmin):
                if w1[j] != w2[j]:
                    adj[w1[j]].add(w2[j])
                    break
       
        ans = []
        vs = {}
       
        def dfs(c):
            if c in vs:
                return vs[c]

            vs[c] = True

            for n in adj[c]:
                if dfs(n):
                    return True

            vs[c] = False

            ans.append(c)
       
        for c in adj:
            if dfs(c) :
                return ""
               
        ans.reverse()

        return "".join(ans)


       

Explaination :







Comments

Popular posts from this blog

May-6 2020 Challenge

  6.   Majority Element Given an array of size  n , find the majority element. The majority element is the element that appears  more than   ⌊ n/2 ⌋  times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input: [3,2,3] Output: 3 Example 2: Input: [2,2,1,1,1,2,2] Output: 2 Solution in Java  class Solution {     public int majorityElement(int[] num) {         int m = num[0], cnt= 1;     for (int i = 1; i < num.length; i++) {         if (cnt == 0) {             m= num[i];             cnt = 1;         } else if (num[i] == m) {             cnt++;         } else              cnt--;    }      return m;...

Leetcode 190. Reverse Bits. Python. Bit Manipulation

  190 .  Reverse Bits Reverse bits of a given 32 bits unsigned integer. Note: Note that in some languages, such as Java, there is no unsigned integer type. In this case, both input and output will be given as a signed integer type. They should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned. In Java, the compiler represents the signed integers using  2's complement notation . Therefore, in  Example 2  above, the input represents the signed integer  -3  and the output represents the signed integer  -1073741825 .   Example 1: Input: n = 00000010100101000001111010011100 Output: 964176192 (00111001011110000010100101000000) Explanation: The input binary string 00000010100101000001111010011100 represents the unsigned integer 43261596, so return 964176192 which its binary representation is 00111001011110000010100101000000 . Example 2: Input: n = 11111111111111111111...

Longest Substring Without Repeating Characters - Leetcode 3 - Python

Given a string s, find the length of the longest substring without repeating characters. class Solution:     def lengthOfLongestSubstring(self, s: str) -> int:         charSet = set()         left = 0         ans = 0         for right in range(len(s)):             while s[right] in charSet:                 charSet.remove(s[left])                 left+=1             charSet.add(s[right])             ans = max(ans, right-left+1)         return ans                  Explained :