Skip to main content

Container with Most Water - Leetcode 11 - Python

 You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]).

Find two lines that together with the x-axis form a container, such that the container contains the most water.

Return the maximum amount of water a container can store.

Notice that you may not slant the container.


 Input: height = [1,8,6,2,5,4,8,3,7]

Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.


class Solution:

    def maxArea(self, height: List[int]) -> int:

        # ans = 0

        # for l in range(len(height)):

        #     for r in range(l+1, len(height)):

        #         ar = (r-l) * min(height[l],height[r])

        #         ans = max(ans, ar)

        # return ans

        

        ans = 0

        l, r = 0, len(height)-1

        

        while l<r:

            ar = (r-l) * min(height[l],height[r])

            ans = max(ans, ar)

            

            if height[l] < height[r]:

                l+=1

            else :

                r -=1

        return ans

            

             

  Explained :



   

Labels:

Comments

Post a Comment

Popular posts from this blog

May-6 2020 Challenge

  6.   Majority Element Given an array of size  n , find the majority element. The majority element is the element that appears  more than   ⌊ n/2 ⌋  times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input: [3,2,3] Output: 3 Example 2: Input: [2,2,1,1,1,2,2] Output: 2 Solution in Java  class Solution {     public int majorityElement(int[] num) {         int m = num[0], cnt= 1;     for (int i = 1; i < num.length; i++) {         if (cnt == 0) {             m= num[i];             cnt = 1;         } else if (num[i] == m) {             cnt++;         } else              cnt--;    }      return m;...
Post a Comment
Read more

Leetcode 190. Reverse Bits. Python. Bit Manipulation

  190 .  Reverse Bits Reverse bits of a given 32 bits unsigned integer. Note: Note that in some languages, such as Java, there is no unsigned integer type. In this case, both input and output will be given as a signed integer type. They should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned. In Java, the compiler represents the signed integers using  2's complement notation . Therefore, in  Example 2  above, the input represents the signed integer  -3  and the output represents the signed integer  -1073741825 .   Example 1: Input: n = 00000010100101000001111010011100 Output: 964176192 (00111001011110000010100101000000) Explanation: The input binary string 00000010100101000001111010011100 represents the unsigned integer 43261596, so return 964176192 which its binary representation is 00111001011110000010100101000000 . Example 2: Input: n = 11111111111111111111...
Post a Comment
Read more

Longest Substring Without Repeating Characters - Leetcode 3 - Python

Given a string s, find the length of the longest substring without repeating characters. class Solution:     def lengthOfLongestSubstring(self, s: str) -> int:         charSet = set()         left = 0         ans = 0         for right in range(len(s)):             while s[right] in charSet:                 charSet.remove(s[left])                 left+=1             charSet.add(s[right])             ans = max(ans, right-left+1)         return ans                  Explained :
Post a Comment
Read more