MAY-30 2020 Challenge

K Closest Points to Origin

We have a list of points on the plane.  Find the K closest points to the origin (0, 0).

(Here, the distance between two points on a plane is the Euclidean distance.)

You may return the answer in any order.  The answer is guaranteed to be unique (except for the order that it is in.)

Example 1:

Input: points = [[1,3],[-2,2]], K = 1
Output: [[-2,2]]
Explanation: 
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].

Example 2:

Input: points = [[3,3],[5,-1],[-2,4]], K = 2
Output: [[3,3],[-2,4]]
(The answer [[-2,4],[3,3]] would also be accepted.)

Note:

1. 1 <= K <= points.length <= 10000
2. -10000 < points[i][0] < 10000
3. -10000 < points[i][1] < 10000

Solution in Java:

class Solution {

    public int[][] kClosest(int[][] points, int K) {

 PriorityQueue<int[]> maxHeap = new PriorityQueue<>(Comparator.comparing(a -> -a[0] * a[0] - a[1] * a[1]));        

        for(int[] point : points){

            maxHeap.add(point);

            if(maxHeap.size() > K)

                maxHeap.remove();

        }

        

        int[][] result = new int[K][2];

       

        while(K-- > 0){

            result[K] = maxHeap.poll();

        }

        

        return result;

    }

}